Pointer to two dimensional array in c programming

Examples of pointers to 2 dimensional array:


What will be output if you will execute following code?


#include<stdio.h>
void main(){

long array[][3]={7l,14l,21l,28l,35l,42l};
long int (*ptr)[2][3]=&array;

printf("%li ",-0[1[0[ptr]]]);


return 0;
}

Output: -28
Explanation:

-0[1[0[ptr]]]
=-1[0[ptr]][0] //From rule array[i]=i[array]
=-0[ptr][1][0]
=-ptr [0] [1] [0]
=-*ptr [0] [1] //From rule array[i]=*(array+i)
=-*(&array) [0] [1]
=-(&array) [0] [1][0]
=-(*&array)[1][0] //From rule *&p=p
=-array[1][0]

array[1][0] means 1*(3)+ 0 = 3rd element of array starting from zero i.e. 28

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2 comments:

padam said...

why 28 not 281????

jayesh sidhwani said...

That is 28(L) L for long and not 281